29=-4.9t^2+12t+29

Solution for 29=-4.9t^2+12t+29 equation:

29=-4.9t^2+12t+29

We move all terms to the left:

29-(-4.9t^2+12t+29)=0

We get rid of parentheses

4.9t^2-12t-29+29=0

We add all the numbers together, and all the variables

4.9t^2-12t=0

a = 4.9; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·4.9·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*4.9}=\frac{0}{9.8}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*4.9}=\frac{24}{9.8}
=2+3.1428571428571/7
$